Problems on Ages

Working methodology: In these problems, two persons initial ages will be given. and before or after several years, their ratio of the ages will be given.  Multiply the ratio of their initial age by x or some variable and take them as their initial age.  Now if final ratio has been given, equate this ratio with that ratio and find x.  Or proceed according to the problem.

Exercise

1.  One year ago Jaya was four times as old as her daughter Nikitha. Six years hence, Mrs.Jaya's age will exceed her daughter's age by 9 years. The ratio of the present ages of Jaya and her daughter is :
a. 9 : 2
b. 11: 3
c. 12: 5
d. 13: 4

2.  Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father ?
a. 30 years
b. 20 years
c. 25 years
d. None of these

3.  A father is twice as old as his son. 20 years ago the age of the father was 12 times the age of the son. The present age of the father is :
a. 44 years
b. 32 years
c. 22 years
d. 45 years

4.  The ratio of the ages of Jaya and Ravi is 2:5. After 8 years, their ages will be in the ratio of 1:2. The difference in their present ages is : ( in years )
a. 24
b. 26
c. 29
d. 32

5. The ages of Ravi  and Rani are in the ratio of 3:5. After 9 years, the ratio of their ages will become 3:4. The present age of Rani is : (in years )
a. 9
b. 15
c. 18
d. 24

6.  The ratio of the ages of Meena and Meera is 4:3. The sum of their ages is 28 years. The ratio of their ages after 8 years will be :
a. 4 : 3
b. 12 : 11
c. 7 : 4
d. 6 : 5

7.  Ten years ago A was half of B in age. If the ratio of their present ages is 3:4 , what will be the total of their present ages ?
a. 8 years
b. 20 years
c. 35 years
d. 45 years

8.  The ratio of Vimal's age and Aruna's age is 3:5 and sum of their ages is 80 years. The ratio of their ages after 10 years will be :
a. 2 : 3
b. 1 : 2
c. 3 : 2
d. 3 : 5