17. The age of Arvind's father is 4 times his age. If 5 years ago, father's age was 7 times the age of his son at the time, what is Arvind's father's present age ?
a. 35 years
b. 40 years
c. 70 years
d. 84 years

Answer: B

Explanation:
Let Arvind's age be x years
Then his father's age = 4 x years
(4x - 5) = 7(x - 5) or 3x = 30 or x = 10
Hence Arvind's father's age is 40 years

18. Pushpa is twice as old as Rita was two years ago. If the difference between their ages is 2 years, how old is Pushpa today ?
a. 6 years
b. 8 years
c. 10 years
d. 12 years
d. None of these

Answer: B

Explanation:
Let Rita's age 2 years ago be x years. Pushpa's present age = (2x) years.
2x - (x + 2)=2 $ \Rightarrow $ x = 4
Pushpa's present age = 8 years

19. Five years ago Vinay's age was one-third of the age of Vikas and now Vinay's age is 17 years. What is the present age of Vikas ?
a. 9 years
b. 36 years
c. 41 years
d. 51 years

Answer: C

Explanation:
Let the present age of Vikas be x years
Then, 17-5 = $\displaystyle\frac{1}{3}$(x - 5)
or x - 5 = 36 or x = 41

20. The sum of the ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. The present ages of the father and son, respectively are,
a. 25 years, 10 years
b. 36 years, 9 years
c. 39 years, 5 years
d. none of these

Answer: B

Explanation:
Let the present ages of father and son be x years and (45-x) years
Then, (x - 5)(45 - x - 5)=4(x - 5)
45 - x - 5 = 4 or x = 36
The present ages of father and son are 36 years and 9 years respectively.

21. Rajan's age is 3 times that of Ashok. In 12 years, Rajan's age will be double the age of Ashok. Rajan's present age is :
a. 27 years
b. 32 years
c. 36 years
d. 40 years

Answer: C

Explanation:
Let Ashok's age be x years
Then, Rajan's age = 3x years
2(x + 12)=(3x + 12) or x = 12
Hence, Rajan's age = 3x years
2(x + 12)=(3x + 12) or x = 12
Hence Rajan's present age is 36 years

22. In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :
a. 19 years
b. 29 years
c. 39 years
d. 49 years

Answer: C

Explanation:
Let the present ages of B and A be x years and (x+9) years respectively. Then 10 years ago B's age is (x - 10) and in the next 10 years A's age is (x + 19)
Given that A's age is twice of B
So (x + 19) = 2 x (x - 10) $ \Rightarrow $ x + 19 = 2x - 20 $ \Rightarrow $ x = 39

23. Mr.Sohanlal is 4 times as old as his son. Four years hence the sum of their ages will be 43 years. The present age of son is :
a. 5 years
b. 7 years
c. 8 years
d. 10 years

Answer: B

Explanation:
Let the son's age be x years
Then, (x + 4) + (4x + 4) = 43
or 5x = 35 or x = 7

24. The sum of the ages of a son and father is 56 years. After 4 years, the age of the father will be three times that of the son. Their ages respectively are:
a. 12 years, 44 years
b. 16 years, 42 years
c. 16 years, 48 years
d. 18 years, 36 years

Answer: A

Explanation:
Let the present ages of son and father be x years
and (56-x) years respectively.
Then (56 - x + 4)=3(x + 4)
or 4x = 48 or x = 12
So their ages are 12 years, 44 years respectively.

25. The sum of the ages of a mother and daughter is 50 years. Also, 5 years ago, the mother's age was 7 times the age of the daughter. The present ages of the mother and daughter respectively are :
a. 35 years, 15 years
b. 38 years, 12 years
c. 40 years, 10 years
d. 42 years, 8 years

Answer: C

Explanation:
Let the daughter's present age be x years. Then, mother's present age = (50-x) years.
Now, 7(x - 5)=(50 - x - 5) or x = 10
So, their present ages are 40 years and 10 years.

9. Jayesh is as much younger to Anil as he is older to Prashant. If the sum of the ages of Anil and Prashant is 48 years, what is the age of Jayesh?
a. 20 years
b. 24 years
c. 30 years
d. Cannot be determined

Answer: B

Explanation:
The given question says, the difference between Anil and Jayesh is same as Jayesh and Prashant.
So A - J = J - P $ \Rightarrow $ 2J = A + P
Given A + P = 48.
So 2J = 48 $ \Rightarrow $ J = 24

Alternate Method:
Let Anil's age = x years. Then, Prasant's age = (48 - x) years. Let the age of Jayesh be P years. Then
P - (48 - x) = x - P $ \Rightarrow $ 2P = 48 or P = 24

10. Three years ago the average age of A and B was 18 years. With C joining them, the average becomes 22 years. How old is C now ?
a. 24 years
b. 27 years
c. 28 years
d. 30 years

Answer: A

Explanation:
Sum of ages of A and B, 3 years ago = $(18 \times 2) = 36$ years. Sum of ages of A,B and C, now = $(22 \times 3) = 66$ years.
Sum of ages of A and B, now =(36 + 6) years = 42 years
C's age = (66 - 42)years = 24 years

11. One year ago the ratio between Samir and Ashok's age was 4:3. One year hence the ratio of their age will be 5:4. What is the sum of their present ages in years?
a. 12 years
b. 15 years
c. 16 years
d. Cannot be determined.

Answer: C

Explanation:
$\displaystyle\frac{{4x + 2}}{{3x + 2}} = \displaystyle\frac{5}{4} \Rightarrow 4(4x + 2) = 5(3x + 2) \Rightarrow x = 2$
Sum of their present ages = (4x + 1 + 3x + 1)=(7x + 2) = 16 years

12. The ratio between the ages of A and B at present is 2: 3 Five years hence the ratio of their ages will be 3:4. What is the present age of A ?
a. 10 years
b. 15 years
c. 25 years
d. Data inadequate

Answer: A

Explanation:
Let the ages of A and B be 2x and 3x years.
$\displaystyle\frac{{2x + 5}}{{3x + 5}} = \displaystyle\frac{3}{4} \Rightarrow 4(2x + 5) = 3(3x + 5) \Rightarrow x = 5$
A's present age = 2x = 10 years

13. The ratio of the ages of father and son at present is 6:1. After 5 years the ratio of will become 7:2. The present age of the son is :
a. 5 years
b. 6 years
c. 9 years
d. 10 years

Answer: A

Explanation:
$\displaystyle\frac{{6x + 5}}{{x + 5}} = \displaystyle\frac{7}{2} \Rightarrow 2(6x + 5) = 7(x + 5) \Rightarrow x = 5$
Son's present age = 5 years

14. Ratio of Ashok's age to Pradeep's age is equal to 4:3 Ashok will be 26 years old after 6 years. How old is Pradeep now ?
a. 12 years
b. 15 years
c. $19\displaystyle\frac{1}{2}$ years
d. 21 years

Answer: B

Explanation:
Let Ashok's age = 4x and Pradeep's age is 3x years
4x + 6=26 $ \Rightarrow $ x = 5
Pradeep's age = 3x = 15 years

15. Kamala got married 6 years ago. Today her age is $1\displaystyle\frac{1}{4}$ times her age at the time of marriage. Her son's age is $\left( {\displaystyle\frac{1}{{10}}} \right)$ times her age. Her son's age is :
a. 2 years
b. 3 years
c. 4 years
d. 5 years

Answer: B

Explanation:
Let Kamala's age 6 years ago be x years, then Kamala's present age = (x+6) years
$(x + 6) = \displaystyle\frac{5}{4}x$ or 4x+24 = 5x or x = 24
So Kamala's present age = 30 years, Son's present age = $\left[ {\displaystyle\frac{1}{{10}} \times 30} \right] = 3$ years

16. 10 years ago, Chandravati's mother was 4 times older than her daughter. After 10 years, the mother will be twice older than the daughter. The present age of Chandravati is:
a. 5 years
b. 10 years
c. 20 years
d. 30 years

Answer: C

Explanation:
Let Chandravati's age 10 years ago be x years.
Mother's age 10 years ago = (4x) years
2(x + 20)=(4x + 20)$ \Rightarrow $ x = 10
Present age of Chandravathi = (x + 10)=20 years

1. Find the remainder when 1201 × 1203 ×1205 × 1207 is divided by 6.
a. 1
b. 2
c. 3
d. 4

Answer: C

Explanation:
$ \Rightarrow {\displaystyle\left( {\frac{N}{D}} \right)_R}$ = ${\left( {\displaystyle\frac{A}{D}} \right)_R}$ × ${\left( {\displaystyle\frac{B}{D}} \right)_R}$ × ${\left( {\displaystyle\frac{C}{D}} \right)_R}...$
By applying the above rule, when 1201, 1203, 1205, 1207 divided by 6, leaves remainders 1, 3, 5, 1. The product of these remainders = 15.
When 15 is divided by 6, Remainder is 3.